Posted by **lisa** on Monday, September 13, 2010 at 11:43pm.

the freezing point of ethanol (C2H5OH) is -114.6C. the molal freezing point depression constant for ethanol is 2.00C/m. what is the freezing point (C) of a solution prepared by dissolving 50.0 g of glycerin (C3H8O3, A nonelectrolyte) in 200 g of ethanol.

any help would be appreciated im very confused.

- molal -
**DrBob222**, Tuesday, September 14, 2010 at 12:02am
moles glycerin = grams/molar mass

solve for moles glycerin.

molality = mole/kg solvent

solve for molality

delta T = K*m

solve for delta T, then freezing point.

- molal -
**lisa**, Wednesday, September 15, 2010 at 7:21pm
thank you looks like i double posted... sorry

- molal -
**lisa**, Wednesday, September 15, 2010 at 7:42pm
i tried to solve it on my own but im confused about the last part, this i what i have so far..

moles of glycerin= 50.0/92.10=0.54

molality=0.54/0.200=2.7

is that right?

im a little confused about the numbers im supposed to use for step 3...

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