Posted by Hannah on .
At t = 0, a stone is dropped from a cliff above a lake; 2.0 seconds later another stone is thrown downward from the same point with an initial speed of 33 m/s. Both stones hit the water at the same instant. Find the height of the cliff.
I have just recently had to answer a very similar question. My prof. has given me the two general eqns to use:
From there, write down your knowns and derive more specific eqns from the general ones... Very vague i know...good luck
Y1 = -(g/2) t^2
Y2 = -33(t-2) -(g/2)((t-2)^2
Set Y1 - Y2 and solve for t.
Use that t to compute Y at that time.
when i solve for t I get an extremely small number like .1998. I don't think I am setting up the problem right or something.