Sunday

December 21, 2014

December 21, 2014

Posted by **peter** on Monday, September 13, 2010 at 9:49pm.

- physics 2 -
**bobpursley**, Monday, September 13, 2010 at 10:23pmSo I assume you have calculus based physics.

integrate the charge thru and angle. let theta begin at the bottom rotate 90 deg for all the neg charge, then from 90 to 180 for the positive charge.

E=INT kdq/r^2 where dq=Q/(pi*r/2)dTheta

integrate from 0 to PI/2, that is E for the lower charge, and it points to the center point of the quadrant (45 deg, by symettry).

Do the same for the + charge, it points away from the center of the upper quadrant.

Now add the two E components. Neat, it point downward, and has value of E*sqrt2

work that out.

**Answer this Question**

**Related Questions**

physics - A thin nonconducting rod is bent to form a semi-circle of radius R. A ...

physics - A plastic rod has been bent into a circle of radius R = 8.80 cm. It ...

physics - A charge of 21 nC is uniformly distributed along a straight rod of ...

College Physics - An electron is released from rest at a perpendicular distance ...

Physics - Electric charge charge is distributed uniformly along a thin rod of ...

Physics - A small, nonconducting ball of mass m=1.0mg and charge q=2.0*10^-8 C (...

Physics - A very large, thin, flat plate of aluminum of area A has a total ...

physics - Consider a thin spherical shell of radius 16.0 cm with a total charge ...

Physics - Consider a “semi-infinite” nonconducting rod (that extends infinitely ...

physics - A thin, uniform rod is hinged at its midpoint. To begin with, one-half...