Posted by Amie on Monday, September 13, 2010 at 7:28pm.
let the side of the square base be x m
let the height be y m
I will assume the box has a lid so the surface area is made up of 2x^ + 4xy
then 2x^2 + 4xy = 12
4xy = 12-2x^2
y = (6-x^2)/(2x)
volume = x^2y
= x^2(6-x^2)/(2x)
= x(6-x^2)/2
for the second, you have similar triangles, so set up a ratio
4/x = 10/(x+d)
10x = 4x + 4d
take it from there
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