Posted by STOW on .
A hockey puck sliding on a frozen lake comes to rest after traveling 160 m.
If its initial velocity is 2.3 m/s, what is its acceleration (assumed constant)?
Answer in units of m/s2.

Physics 
TutorCat,
The distance = (1/2)*(acceleration)*(time)^2 + (initial velocity)*(time)
substitute:
acceleration= (final velocityinitial velocity)/time
The distance = (1/2)*[(final velocityinitial velocity)/time]*(time)^2 + (initial velocity)*(time)
Find time & plug back into acceleration formula!