Calculus..Need Help Soon
posted by Leanna .
If the solutions of f(x)=0 are 1 and 2, then the solutions of f(2x)=0 are
a)1 and 2
b) 1/2 and 1
c) 2 and 4
d)2 and 4
2)1/2 and 1

If the solutions are 1 and 2, and assuming f(x) is a polynomial, then
f(x)=k(x1)(x+2)
and
f(2x) = k(2x1)(2x+2)
implying
2x1=0 or (2x+2)=0
Solve for x.