balance ___ch3ch2cooh + __o2 yields __co2 + ___h2o
youtube(dot)com/watch?v=vO9VgitCx04
I must point out that ch3cooh doesn't mean a thing except gibberish.
To balance the chemical equation:
C3H8COOH + O2 → CO2 + H2O
We need to ensure that there is an equal number of atoms on both sides of the equation.
First, let's balance the carbon atoms. There are 3 carbon atoms on the left side (in C3H8COOH) and only 1 on the right side (in CO2). To equalize the carbon atoms, we need to put a coefficient of 3 in front of CO2:
C3H8COOH + O2 → 3CO2 + H2O
Next, let's balance the hydrogenatoms. There are 8 hydrogen atoms on the left side (in C3H8COOH) and only 2 on the right side (in H2O). To equalize the hydrogen atoms, we need to put a coefficient of 4 in front of H2O:
C3H8COOH + O2 → 3CO2 + 4H2O
Finally, let's balance the oxygen atoms. There are 2 oxygen atoms on the left side (in O2) and 10 on the right side (in 3CO2 and 4H2O). To equalize the oxygen atoms, we need to put a coefficient of 5/2 (or 2.5) in front of O2:
C3H8COOH + 2.5O2 → 3CO2 + 4H2O
However, it's best to avoid fractional coefficients in balanced equations. To eliminate the fractional coefficient, you can multiply all the coefficients by 2:
2C3H8COOH + 5O2 → 6CO2 + 8H2O
Therefore, the balanced chemical equation is:
2C3H8COOH + 5O2 → 6CO2 + 8H2O