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November 21, 2014

November 21, 2014

Posted by **Jamie** on Sunday, September 12, 2010 at 9:44pm.

1. f(x) = -x^3 + x + 1 is an odd function

2. f(x) = x^3 -ax^2 + bx represents a cubic equation having no constant term ...(I'm thinking true?)

3. If f(x) = x/x+2 then f^-1 (x) = 2x/1-x ...(my guess is false?)

4. The equation x^3 - 12x + 16 = 0 has a double root at x = -4

- Math - True or False -
**MathMate**, Monday, September 13, 2010 at 7:35am1. check if f(x)=-f(-x)

2. correct

3. If f(x)=x/(x+2)

solve for y in x=y/(y+2) where y=f^{-1}(x)

4. Substitute x=-4 in the equation and see if the left-hand-side vanishes.

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