Jason drives due west with a speed of 35.0 mi/hr for 30 mins, then continues in the same direction with a speed of 60.0 mi/hr for 2.00 hr then drives farther west at 25.0 mi/hr for 10.0 mins. What is his average velocity?
To find the average velocity, we need to calculate the total displacement and total time taken.
First, let's calculate the displacement during each segment:
Segment 1: Jason drives for 30 mins (0.5 hr) at a speed of 35.0 mi/hr. The displacement for this segment can be found using the formula: displacement = speed × time. Therefore, the displacement for this segment is 35.0 mi/hr × 0.5 hr = 17.5 mi west.
Segment 2: Jason drives for 2.00 hr at a speed of 60.0 mi/hr. The displacement for this segment is 60.0 mi/hr × 2.00 hr = 120.0 mi west.
Segment 3: Jason drives for 10 mins (0.17 hr) at a speed of 25.0 mi/hr. The displacement for this segment is 25.0 mi/hr × 0.17 hr = 4.25 mi west.
Now, let's calculate the total displacement by summing up the displacements from each segment:
Total displacement = 17.5 mi west + 120.0 mi west + 4.25 mi west = 141.75 mi west.
The total time taken is the sum of the individual time durations:
Total time = 30 mins (0.5 hr) + 2.00 hr + 10 mins (0.17 hr) = 2.67 hr.
Finally, we can calculate the average velocity using the formula: average velocity = total displacement ÷ total time.
Average velocity = 141.75 mi west ÷ 2.67 hr ≈ 53.1 mi/hr.
Therefore, Jason's average velocity is approximately 53.1 mi/hr directed west.
d1 = 35 mi/hr * 0.5 hr = 17.5 mi,
d2 = 60 mi/hr * 2 hr = 120 mi,
d3 = 25 mi/hr * 1/6 hr = 4.17 mi.
d = 17.5 + 120 + 4.17 = 141.67 miles,
t = 0.5 + 2.0 + 1/6 = 2.67 hrs,
Vavg = d / t = 141.67/2.67 = 53.13 mi/hr.
8
To find Jason's average velocity, we need to calculate the total displacement and total time taken.
First, let's calculate the displacement during each leg of the trip:
1. Leg 1: Jason drives at a speed of 35.0 mi/hr for 30 minutes. Since speed is given, we can calculate the distance covered:
Distance = Speed × Time
= 35.0 mi/hr × (30/60) hr
= 17.5 miles
2. Leg 2: Jason drives at a speed of 60.0 mi/hr for 2.00 hours:
Distance = Speed × Time
= 60.0 mi/hr × 2.00 hr
= 120 miles
3. Leg 3: Jason drives at a speed of 25.0 mi/hr for 10 minutes:
Distance = Speed × Time
= 25.0 mi/hr × (10/60) hr
= 4.17 miles (rounded to two decimal places)
Now, let's calculate the total displacement:
Total Displacement = Displacement Leg 1 + Displacement Leg 2 + Displacement Leg 3
= 17.5 miles + 120 miles + 4.17 miles
= 141.67 miles (rounded to two decimal places)
Next, let's calculate the total time taken:
Total Time = Time Leg 1 + Time Leg 2 + Time Leg 3
= 30 minutes + 2.00 hours + 10 minutes
= 2.5 hours
Finally, let's calculate the average velocity:
Average Velocity = Total Displacement / Total Time
= 141.67 miles / 2.5 hours
= 56.67 mi/hr (rounded to two decimal places)
Therefore, Jason's average velocity is 56.67 mi/hr.
Well, let's do some math to find Jason's average velocity. To calculate average velocity, we need to find the total displacement and divide it by the total time taken.
In the first leg of the journey, Jason drives at a speed of 35.0 mi/hr for 30 mins. This means he covers a distance of (35.0 mi/hr) * (0.5 hr) = 17.5 miles.
In the second leg, Jason drives at a speed of 60.0 mi/hr for 2.00 hours, covering a distance of (60.0 mi/hr) * (2.00 hr) = 120 miles.
In the final leg, he drives at a speed of 25.0 mi/hr for 10.0 mins, which means he travels a distance of (25.0 mi/hr) * (10.0 min/60 min) = 4.17 miles.
Adding up these three distances, we get a total displacement of 17.5 miles + 120 miles + 4.17 miles = 141.67 miles.
Now, let's calculate the total time taken. Jason spends 30 mins + 2.00 hours + 10.0 mins = 140 minutes on his journey, which is equivalent to 2.33 hours.
To get the average velocity, we divide the total displacement by the total time: 141.67 miles / 2.33 hours ≈ 60.83 mi/hr.
So, Jason's average velocity is approximately 60.83 mi/hr. Well, it seems like Jason was in quite a hurry to get somewhere!