Posted by **Denise** on Sunday, September 12, 2010 at 8:09pm.

I really need help with this problem.

A conical vessel is 12 feet across the top and 15 feet deep. If it contains a liquid weighing p lbs/ft^3 (p=62.5 lbs/ft^3)to a depth of 10 feet. Find the work done in pumping the liquid to a height of 3 feet above the vessel.

- Calculus -
**drwls**, Sunday, September 12, 2010 at 8:16pm
The center of gravity of the cone is 1/3 of the height of 5m from the bottom, which is 10 feet from the top. To raise all the liquid 3 feet above the top, tha average mass is raised 3 + 10 = 13 feet.

The work required is the weight of the water in the conical tank,

W = (1/3)*pi*R^2*H*g

multiplied by 13 feet.

The answer will be in ft-lb.

## Answer this Question

## Related Questions

- Calculus - A conical vessel is 12 feet across the top and 15 feet deep. If it ...
- Math-How do I do this problem? - An inverted conical tank (with vertex down) is ...
- calculus-rate problem - A conical tank (with vertex down) is 10 feet acros the ...
- cal - A conical tank (with vertex down) is 12 feet across the top and 18 feet ...
- Math help, Please - An inverted conical tank (with vertex down) is 14 feet ...
- calculus - Water is flowing freely from the bottom of a conical tank which is 12...
- Calculus - You have a conical tank, vertex down, which is 12 feet across the top...
- calculus - A conical water tank with vertex down has a radius of 12 feet at the ...
- calculus - Water is pouring into a conical vessel 15cm deep and having a radius ...
- Calculus (math) - A conical water tank with vertex down has a radius of 12 feet ...