Monday

April 21, 2014

April 21, 2014

Posted by **Denise** on Sunday, September 12, 2010 at 8:09pm.

A conical vessel is 12 feet across the top and 15 feet deep. If it contains a liquid weighing p lbs/ft^3 (p=62.5 lbs/ft^3)to a depth of 10 feet. Find the work done in pumping the liquid to a height of 3 feet above the vessel.

- Calculus -
**drwls**, Sunday, September 12, 2010 at 8:16pmThe center of gravity of the cone is 1/3 of the height of 5m from the bottom, which is 10 feet from the top. To raise all the liquid 3 feet above the top, tha average mass is raised 3 + 10 = 13 feet.

The work required is the weight of the water in the conical tank,

W = (1/3)*pi*R^2*H*g

multiplied by 13 feet.

The answer will be in ft-lb.

**Related Questions**

Calculus - A conical vessel is 12 feet across the top and 15 feet deep. If it ...

cal - A conical tank (with vertex down) is 12 feet across the top and 18 feet ...

Calculus - You have a conical tank, vertex down, which is 12 feet across the top...

calculus-rate problem - A conical tank (with vertex down) is 10 feet acros the ...

calculus - Water is pouring into a conical vessel 15cm deep and having a radius ...

calculus - A conical water tank with vertex down has a radius of 12 feet at the ...

Calculus (Definite Integrals - Work) - Recall that work is defined to be force ...

math - calc - A conical water tank with vertex down has a radius of 12 feet at ...

math - calc - A conical water tank with vertex down has a radius of 12 feet at ...

calculus - A conical tank( with vertex down) is 10 feet across the top and 18 ...