Posted by Emily on Sunday, September 12, 2010 at 7:45pm.
Twice as far.
Here's the reason
The maximum height when you throw vertically is V^2/2g.
(That is easily proven using conservation of energy)
The RANGE X at any angle A is
2 sinAcosA/V^2/g, and the maximum range is obtainec at a A = 45 degree angle, for which
Xmax = V^2/g
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