posted by Emily on .
If you can throw a ball vertically upward to a height h = 30.1 m, what is the maximum horizontal range over which you can throw the same ball, assuming you throw it at the same initial speed
Twice as far.
Here's the reason
The maximum height when you throw vertically is V^2/2g.
(That is easily proven using conservation of energy)
The RANGE X at any angle A is
2 sinAcosA/V^2/g, and the maximum range is obtainec at a A = 45 degree angle, for which
Xmax = V^2/g