Thursday

January 29, 2015

January 29, 2015

Posted by **Lauren** on Sunday, September 12, 2010 at 6:42pm.

1 A B

----- = --- + ---

k(k+1) k k+1

- Pre Calc -
**Lauren**, Sunday, September 12, 2010 at 6:43pmthe 1 is over k(k+1), and the A is over k, and the B is over k+1

- Pre Calc -
**Anonymous**, Sunday, September 12, 2010 at 9:45pmcommon denominator: k(k+1)

1/[(k)(k+1)]=A(k+1)/[(k)(k+1)] + B(k)/[(k)(k+1)]

1/[(k)(k+1)]= [ A(k+1)+ B(k)]/ [(k)(k+1)]

cross multiply:

[(k)(k+1)]= [ A(k+1)+ B(k)][(k)(k+1)]

cancel like terms:

1= [ A(k+1)+ B(k)]

solve for k!

**Answer this Question**

**Related Questions**

Pre-Calc - I'm stuck on a pre-calc problem. I need to find y as a function of x...

Pre-Calc - Can you show me how to find the rectangular equation of r=2costheta...

Pre Calc - Solve for x: |4x+6|-|2x-1|<5

pre calc - f(x)=1/x+2 how do i solve this

pre-calc - how do i solve this w(4-w^2)=8-w^3

Pre-Calc - How do I solve this equation? 4^x * (1/2)^3-2x = 8*(2^x)^2

Pre-calc - Solve 3.3= 1.005^n

math pre calc - solve for x. 8^6+3x=16

pre-calc - How do u solve (f-g)(x) when f(x)=4x/7 +7 and g(x)=-6/x Ok so its (f-...

Pre-Calc - How would I solve: X^(4/3)+X^(2/3)=28