Posted by **Jenniah** on Sunday, September 12, 2010 at 6:12pm.

In 1992, the life expectancy of males in a certain country was 61.6 years. In 1995, it was 65.2 years. Let E represent the life expectancy in year t and let t represent the number of years since 1990.

The linear function E(t) that fits the data is... E(t)=_____t + _______ (round to nearest 10th)

Use the function to predict the life expectancy of males in 2006.

E(14) = ___________ (round to nearest 10th)

I come up with:

E(t)=6t + 68.3--- for the 1st answer and

E(14) = 74.9

i.e. 74.88 rounded to nearest 10th

Is it right? if not please, please show and correct me!

## Answer This Question

## Related Questions

- algebra - In 1992 the life expectancy of males in a certain country was 63.4 ...
- Algebra - In 1991, the life expectancy of males in a certain country was 67.2 ...
- algebra - in 1990, the life expectancy of males in a certain country was 68.1 ...
- algebra - In 1990, the life expectancy of males in a certain country was 62.1 ...
- algebra - In 1990, the life expectancy of males in a certain country was 62.1 ...
- Algebra - In 1992, the life expectancy of males in a certain country was 63.8 ...
- Algebra - In 1992, the life expectancy of males in a certain country was 71.4 ...
- algebra - In 1995, the life expectancy of males in a certain country was 73.7 ...
- math - In 1990, the life expectancy of males in a certain country was 62.1 years...
- math - In 1990, the life expectancy of males in a certain country was 62.1 years...

More Related Questions