the area of the rectangular playground enclosure at South School is 500 square meters. The length of the playground is 5 meters longer than the width. Find the dimensions of the playground, in meters.

area=l*w=(w+500)w

500=w^2+500w
put it in standard form, solve. use the quadratic equation.

the length of a rectangle is 6m than width area is 55m2 what is dimensions of rectangle

the length of a rectangle is 6m than the width. the area is 55m2 what are the dimensions of the rectangle.

To find the dimensions of the rectangular playground enclosure, let's represent the width of the playground as "w" meters.

Based on the given information, we know that the length of the playground is 5 meters longer than the width, so the length can be represented as "w + 5" meters.

The formula to find the area of a rectangle is:

Area = Length x Width

In this case, the area is given as 500 square meters. We can substitute the values into the formula and solve for the unknowns:

500 = (w + 5)w

To solve this equation for w, we first need to distribute the w on the right-hand side:

500 = w^2 + 5w

Now, we rearrange the equation in standard quadratic form:

w^2 + 5w - 500 = 0

To solve this quadratic equation, we can either factor it or use the quadratic formula. In this case, it seems easier to use factoring:

(w + 25)(w - 20) = 0

Setting each factor to zero and solving for w, we get:

w + 25 = 0 or w - 20 = 0

w = -25 or w = 20

Since the width of the playground cannot be negative, we discard w = -25.

Therefore, the width of the playground is 20 meters.

To find the length, we substitute this value back into the given relationship:

Length = Width + 5
Length = 20 + 5
Length = 25 meters

So, the dimensions of the playground are 20 meters by 25 meters.