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September 3, 2014

September 3, 2014

Posted by **premadonna** on Sunday, September 12, 2010 at 12:50am.

- trig -
**drwls**, Sunday, September 12, 2010 at 7:12amLet the height of the mountain (in feet) be H.

Let the initial horizontal distance from the mountain peak be X.

H/X = tan 23.7 = 0.43897

H/(X-5280) = tan 30.633 =0.59218

Solve the two equations in two unknowns (X and H)

H - 0.43897X = 0

H - 0.59218X = -3126.7

- trig -
**Elonzo**, Thursday, February 10, 2011 at 2:39pm20420

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