Sunday

March 29, 2015

March 29, 2015

Posted by **Amy~** on Sunday, September 12, 2010 at 12:00am.

(the total weight of the desired blend is 100 lbs)

How would I solve this?

The equation would 3.90 = 2.75x + 5x ?

3.90(100) = 2.75x + 5x

- Math Word Problem -
**drwls**, Sunday, September 12, 2010 at 7:39amLet there be x lb of the expensive coffee and y lb of the inexpensive coffee.

x + y = 100

5x + 2.75 y = 3.90*100 = 390

Now solve for both x and y.

5x + 5y = 500

2.25 y = 110

y = 48.89

x = 51.11

It is almost a 50/50 blend

**Answer this Question**

**Related Questions**

Algebra - A coffee manufacturer wants to market a new blend of coffee that will ...

maths - A coffee manufacture wants a new blend of coffee that sell for $3.90 per...

math - the manager of a starbucks store plans to mix A grade coffee that cost 9....

math - I need to solve as an equation. A coffee merchant has coffee beans that ...

Algebra - The vendor of a coffee cart mixes coffee beans that cost $7 per pound ...

algebra - Mixture Problems Template – Price Problems Copy the problem from the ...

algebra - The vendor of a coffee cart mixes coffee beans that cost $8 per pound ...

algebra 1 - Sarah blends coffee for Tasti-Delight. She needs to prepare 170 lbs ...

algebra - Sarah blends coffee for Tasti-Delight. She needs to prepare 170 lbs of...

algebra - The vendor of a coffee cart mixes coffee beans that cost $8 per pound ...