How many grams of na3po4 will be needed to produce 425ml of a solution that has a concentration of na+ ions of 1.30 M?
Na^+ = 1.30 M
Na3PO4 = 1.30/3 since there are 3 Na^+ in 1 molecule of Na3PO4.
M = moles/L
Substitute M and L; solve for moles.
Then moles = grams/molar mass.
You have moles and molar mass; solve for grams.
In the future remember that na3po4 doesn't mean a thing; it's Na3PO4.
30.2 g
I agree.
To calculate the number of grams of Na3PO4 needed to produce a solution with a given concentration, you need to use the following steps:
Step 1: Determine the molar mass of Na3PO4.
The molar mass of Na3PO4 can be calculated by adding up the atomic masses of sodium (Na), phosphorus (P), and oxygen (O). The atomic mass of sodium is 22.99 g/mol, phosphorus is 30.97 g/mol, and oxygen is 16.00 g/mol. So, the molar mass of Na3PO4 is:
Molar mass of Na3PO4 = (3 x atomic mass of Na) + atomic mass of P + (4 x atomic mass of O)
= (3 x 22.99 g/mol) + 30.97 g/mol + (4 x 16.00 g/mol)
= 69.0 g/mol + 30.97 g/mol + 64.0 g/mol
= 164.97 g/mol
Therefore, the molar mass of Na3PO4 is 164.97 g/mol.
Step 2: Calculate the number of moles of Na+ ions needed.
To find the number of moles of Na+ ions needed, you need to use the concentration and volume of the solution. The concentration is given as 1.30 M, which means there are 1.30 moles of Na+ ions in 1 liter (1000 ml) of solution. So, for a volume of 425 ml (0.425 L), the number of moles of Na+ ions needed can be calculated as:
Number of moles of Na+ = concentration x volume
= 1.30 M x 0.425 L
Step 3: Convert moles of Na+ ions to grams of Na3PO4.
Since Na3PO4 has a 1:3 molar ratio with Na+, we can use stoichiometry to calculate the number of moles of Na3PO4 needed. From the balanced chemical equation, we know that 1 mole of Na3PO4 produces 3 moles of Na+. Therefore, the number of moles of Na3PO4 needed is:
Number of moles of Na3PO4 = (Number of moles of Na+) / 3
Step 4: Calculate the mass of Na3PO4 needed.
Finally, you can calculate the mass of Na3PO4 needed by multiplying the number of moles of Na3PO4 by its molar mass:
Mass of Na3PO4 = Number of moles of Na3PO4 x Molar mass of Na3PO4
By following these steps, you can apply the given concentration and volume information to find the mass of Na3PO4 needed to produce a solution with a concentration of Na+ ions of 1.30 M.