Posted by **Joy** on Saturday, September 11, 2010 at 3:08pm.

A car is traveling around a horizontal circular track with radius r = 240 m at a constant speed v = 25 m/s as shown. The angle čA = 34° above the x axis, and the angle čB = 65° below the x axis.

I found the car's acceleration to be 2.6 m/s^2 (a=v^2/r).

Now I need to know the x component of the car's acceleration when it is at point A.

I'm not sure how to go about solving this.

- Physics -
**joi**, Tuesday, May 10, 2011 at 3:10pm
whats the answerrrr ?

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