Algebra
posted by Anonymous .
Suppose that the area of a square is fortyone times its perimeter. Find the length of a side of the square.

41(x+x+x+x)=x^2
since the area of a square is fortyone times its perimeter, I multiply 41 on the perimeter side to set the perimeter equal to the area
solve for x. you'll get two answers. eliminate the one that is equal to zero since a measure of length cannot equal to zero! 
thank you ! I solved it