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December 18, 2014

December 18, 2014

Posted by **Denise** on Saturday, September 11, 2010 at 1:26pm.

- calculus -
**Anonymous**, Saturday, September 11, 2010 at 2:43pm∫ √[1 + (dx/dy)^2] dx (from a to b)

first, take the derivative of x and plug it into dx/dy, square that

then, add 1 and square root it

last, take the antiderivative

- calculus -
**Anonymous**, Saturday, September 11, 2010 at 2:45pmand of course, plug in the numbers

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