Calculate the mass percent composition of carbon in each the following carbon compounds.
a) C_4H_10
b) C_6H_10
c) CCl_2F_2
d) C_8H_13O_5N
find the mass of carbon and the mass of the carbon compound
mass percent composition of carbon
= mass of carbon/ mass of carbon compound
x 100%
for example:
for a)
mass of carbon=4(12)
mass of carbon compound=4(12)+10(1)
48/58 x 100%
To calculate the mass percent composition of carbon in a compound, you need to follow these steps:
Step 1: Determine the molar masses of all the elements present in the compound.
Step 2: Calculate the total molar mass of the compound.
Step 3: Find the molar mass of carbon in the compound.
Step 4: Divide the molar mass of carbon by the total molar mass of the compound and multiply by 100 to obtain the mass percent composition.
Let's calculate the mass percent composition of carbon for each of the given compounds:
a) C4H10:
In this compound, we have 4 carbon atoms and 10 hydrogen atoms.
Step 1: Molar mass of carbon (C) = 12.01 g/mol
Molar mass of hydrogen (H) = 1.01 g/mol
Step 2: Total molar mass of the compound = (4 * 12.01) + (10 * 1.01) = 58.14 g/mol
Step 3: Molar mass of carbon (C) = 4 * 12.01 = 48.04 g/mol
Step 4: Mass percent composition of carbon = (48.04 / 58.14) * 100 = 82.68%
Therefore, the mass percent composition of carbon in C4H10 is approximately 82.68%.
b) C6H10:
In this compound, we have 6 carbon atoms and 10 hydrogen atoms.
Repeat the same steps as above to calculate the mass percent composition of carbon in C6H10.
Step 1: Molar mass of carbon (C) = 12.01 g/mol
Molar mass of hydrogen (H) = 1.01 g/mol
Step 2: Total molar mass of the compound = (6 * 12.01) + (10 * 1.01) = 82.13 g/mol
Step 3: Molar mass of carbon (C) = 6 * 12.01 = 72.06 g/mol
Step 4: Mass percent composition of carbon = (72.06 / 82.13) * 100 = 87.75%
Therefore, the mass percent composition of carbon in C6H10 is approximately 87.75%.
c) CCl2F2:
In this compound, we have 1 carbon atom, 2 chlorine atoms, and 2 fluorine atoms.
Repeat the same steps as above to calculate the mass percent composition of carbon in CCl2F2.
Step 1: Molar mass of carbon (C) = 12.01 g/mol
Molar mass of chlorine (Cl) = 35.45 g/mol
Molar mass of fluorine (F) = 18.99 g/mol
Step 2: Total molar mass of the compound = 12.01 + (2 * 35.45) + (2 * 18.99) = 129.89 g/mol
Step 3: Molar mass of carbon (C) = 12.01 g/mol
Step 4: Mass percent composition of carbon = (12.01 / 129.89) * 100 = 9.24%
Therefore, the mass percent composition of carbon in CCl2F2 is approximately 9.24%.
d) C8H13O5N:
In this compound, we have 8 carbon atoms, 13 hydrogen atoms, 5 oxygen atoms, and 1 nitrogen atom.
Repeat the same steps as above to calculate the mass percent composition of carbon in C8H13O5N.
Step 1: Molar mass of carbon (C) = 12.01 g/mol
Molar mass of hydrogen (H) = 1.01 g/mol
Molar mass of oxygen (O) = 16.00 g/mol
Molar mass of nitrogen (N) = 14.01 g/mol
Step 2: Total molar mass of the compound = (8 * 12.01) + (13 * 1.01) + (5 * 16.00) + 14.01 = 227.24 g/mol
Step 3: Molar mass of carbon (C) = 8 * 12.01 = 96.08 g/mol
Step 4: Mass percent composition of carbon = (96.08 / 227.24) * 100 = 42.28%
Therefore, the mass percent composition of carbon in C8H13O5N is approximately 42.28%.