A group of 9 trout (considered the population) were isolated in a pond and fed a special food mixture called Grow Em Fast. At the end of the experimental period, the weights of the trout were (in grams): 124, 125, 123, 120, 124, 127, 125, 126 and 121. Another special mixture, Fatso 1B, was used in another pond. The mean of the population was computed to be 126.9 grams and the standard deviation was 1.20 grams. Which food results in a more uniform weight?
A) Grow Em Fast
B) Fatso 1B
C) No difference in uniformity of performance.
D) Insufficient information.
Calculate the standard deviation for Grow Em Fast and compare to 1.2 for Fatso 1B.
To get standard deviation, first find mean. Get difference of each score from mean, square those differences and find their sum. Divide by n (9), and the square root of that quotient will be the standard deviation.
fatso 1b
To determine which food results in a more uniform weight, we need to compare the standard deviation of the weights for the two food mixtures.
In this case, we have the standard deviation for the population fed Grow Em Fast, which is 1.20 grams. However, we do not have the weights of the trout fed Fatso 1B, so we cannot calculate the standard deviation for that group.
Since we do not have the necessary information to calculate the standard deviation for the group fed Fatso 1B, the correct answer is D) Insufficient information.