1) 6 = (12/√x) + 2
2) 7x – 3 = 4x + 9
3) 12 – 4x = x2
4) (5 + x)/10 = 12
5) 10/(5 + x) = 12
1. Sorry, I was never good with radicals.
2. 7x-3=4x+9
You want to get the variables (letters) on one side and numbers on the other.
Add 3 to both sides:
7x=4x+12
Subtract 4x from both sides:
3x=12
Divide both sides by 3:
x=?
3. 12-4x=x^2
x^2+4x-12
Now factor it. You are looking for two numbers that add to your middle term (4) and multiply to your last term (-12).
4. (5+x)/10=12
Multiply both sides by 10:
5+x=120
Subtract 5 from both sides:
x=?
5. Not really sure how to start this one..
Post your answers to the other ones if you'd like them checked.