Homework Help: Math

Posted by Mark G on Friday, September 10, 2010 at 9:50pm.

Eva invested a certain amount of money at 9% interest and $1600 more than that amount at 11%. Her total yearly interest was $760. How much did she invest at each rate?

Math - PsyDAG, Saturday, September 11, 2010 at 11:21am
Let x = amount at 9% and y = amount at 11%

y = x + 1600

.09x + .11y = 760

Substitute x + 1600 for y in the second equation and solve for y. Put that value in first equation to find x. To check, put both values in second equation.

Answer this Question

Related Questions

Math - Eva invested a certain amount of money at 9% interest and $1600 more than...
math - Eva invested a certain amount of money at 5% interest and $1500 more than...
Algebra - Eva invested a certain amount of money at 12% interest and $1500 more ...
algebra - A total of $12,000 is invested in two funds paying 9% and 11% simple ...
Algebra - I invested $42,000 in three funds paying 5%, 7%, and 9% simple ...
math - A student invests two sums of money at 3% and 4% interest, receiving a ...
Math - An investor invested money @ 5% and $49,000 more than 3 times the amount...
algebra interest word problem - Solve the problem. Roberto invested some money ...
Algebra - Compare the future amounts (A) you would have if the money were ...
Math - Two investments are made totaling $4800. In the first year they yield a ...

For Further Reading

First Name:
School Subject:
Answer: