Posted by **Melisa** on Friday, September 10, 2010 at 8:51pm.

A car is driven east for a distance of 49 km, then north for 35 km, and then in a direction 33° east of north for 27 km. Draw the vector diagram and determine the total displacement of the car from its starting point.

What is the magnitude and direction?

- physics -
**drwls**, Saturday, September 11, 2010 at 1:41am
We don't do graphs.

Add the three displacement vectors to get the total displacement.

I recommend adding the x (east) and y (north) components for the total displacement vector. You won't need a vector diagram to answer the problem (unless you really have to turn one in).

- physics -
**Anonymous**, Sunday, December 19, 2010 at 5:03am
A CAR IS 150 KM FROM EAST TO NORTH THE MAGNITUDE IS 13.4

## Answer this Question

## Related Questions

- physics - A car is driven east for a distance of 49 km, then north for 35 km, ...
- physics - A car is driven east for a distance of 50 km, then north for 30 km, ...
- physics - A car is driven east for a distance of 45 km, then north for 33 km, ...
- Physics - A car is driven east for a distance of 46 km, then north for 27 km, ...
- physics - A car is driven east for a distance of 88 km, then north for 28 km, ...
- Science - A car is driven east for a distance of 43 km, then north for 20 km, ...
- Physics - A car is driven east for a distance of 46 km, then north for 29 km, ...
- physics - A car is driven east for a distance of 41 km, then north for 21 km, ...
- physics - A car is driven east for a distance of 49 km, then north for 21 km, ...
- physics - A car is driven east for a distance of 42 km, then north for 25 km, ...

More Related Questions