Friday

July 25, 2014

July 25, 2014

Posted by **Gina** on Friday, September 10, 2010 at 3:13am.

If yes, by how much? If not, by how much did it miss?

- Physics -
**drwls**, Friday, September 10, 2010 at 6:50amWrite the equations for ball height Z and horizontal location X vs time. Assume the ball is served perpendicular to the net, "down the middle" (Y=constant), not to a side line.

X = 19.4 cos 7.28 t = 19.24 t

When the ball reaches the net, X = 11.83 m, so t = 0.6149 s

Y = 1.80 + 19.4 sin 7.28 t - (9.80/2)t^2

= 1.80 + 2.468 t - 4.90 t^2

Solve for the Y height when t = 0.6149 s when the ball reaches the net), and compare it to the height of the net.

I get Y to exceed the net height when it reaches the net.

- Physics -
**drwls**, Friday, September 10, 2010 at 6:54amThe equation for Y should have been for the ball height, Z.

**Related Questions**

Physics - You serve a tennis ball from a height of 2.29 m above the ground. The ...

physics - As a tennis ball is struck, it departs from the racket horizontally ...

Physics - A tennis ball is struck and departs from the racket horizontally with ...

Physics - A tennis ball is struck and departs from the racket horizontally with ...

physics - A tennis ball is struck and departs from the racket horizontally with ...

physics - A tennis ball is struck and departs from the racket horizontally with ...

Physics - As a tennis ball is struck, it departs from the racket horizontally ...

physics - a tennis player swings her 1000g racket with a speed of 6.00 m/s. she ...

WR - A tennis ball is struck and departs from the racket horizontally with a ...

Physics - A tennis ball is struck such that it leaves the racket horizontally ...