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March 30, 2015

March 30, 2015

Posted by **Gina** on Friday, September 10, 2010 at 3:13am.

If yes, by how much? If not, by how much did it miss?

- Physics -
**drwls**, Friday, September 10, 2010 at 6:50amWrite the equations for ball height Z and horizontal location X vs time. Assume the ball is served perpendicular to the net, "down the middle" (Y=constant), not to a side line.

X = 19.4 cos 7.28 t = 19.24 t

When the ball reaches the net, X = 11.83 m, so t = 0.6149 s

Y = 1.80 + 19.4 sin 7.28 t - (9.80/2)t^2

= 1.80 + 2.468 t - 4.90 t^2

Solve for the Y height when t = 0.6149 s when the ball reaches the net), and compare it to the height of the net.

I get Y to exceed the net height when it reaches the net.

- Physics -
**drwls**, Friday, September 10, 2010 at 6:54amThe equation for Y should have been for the ball height, Z.

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