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October 30, 2014

October 30, 2014

Posted by **bethany** on Thursday, September 9, 2010 at 11:27pm.

- physics -
**drwls**, Friday, September 10, 2010 at 7:46amFirst calculate the time to fall Y = 5.00 m and Y = 150 m for the first (dropped) stone. t = sqrt(2Y/g)

The times are 1.02 s and 5.53 s

Then calculate the speed V the second stone must be thrown to reach the ground at the same time.

150 = V*(t-1.02) + (g/2)(t-1.02)^2

Solve for V

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