a plane travels 5.0 x 10^2 while being accelerated uniformly from rest at the rate of 5.0 m/s. what final velocity does it attain?

70.7m/s

To find the final velocity attained by the plane, we can use the equation of motion for uniformly accelerated motion:

v^2 = u^2 + 2as

Where:
v = final velocity (what we are trying to find)
u = initial velocity (which is 0 m/s as the plane starts from rest)
a = acceleration (given as 5.0 m/s^2)
s = distance traveled (given as 5.0 x 10^2 m)

We'll substitute the known values into the equation:

v^2 = (0 m/s)^2 + 2 * (5.0 m/s^2) * (5.0 x 10^2 m)

v^2 = 0 + 1000 x 5.0

v^2 = 5000

To solve for v, we need to take the square root of both sides:

v = √5000

Now, let's calculate the final velocity (v):

v ≈ 70.7107 m/s (rounded to four decimal places)

So, the plane attains a final velocity of approximately 70.7107 m/s.

(5.0x10^2)/5.0