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March 30, 2015

March 30, 2015

Posted by **G** on Thursday, September 9, 2010 at 3:46pm.

Question part Points Submissions 1 2 3

0/1 0/1 0/1

0/7 3/7 2/7

Total 0/3 A vector A has a magnitude of 49.0 m and points in a direction 20.0° below the x axis. A second vector, B, has a magnitude of 70.0 m and points in a direction 41.0° above the x axis.

Find the magnitude and direction of the vector D.

- Physics -
**MathMate**, Thursday, September 9, 2010 at 8:06pmI do not see how the vector D is defined. I have to assume that vector D is the sum of vectors A and B.

To find the resultant (sum) of vectors, you would sum the x- and y-components by resolving the vectors in the x-direction (Pcos(θ)) and y-direction (Psin(θ)).

The magnitude of the resultant is

sqrt(SumX²+SumY²)

and the direction is obtained by

atan(SumY/SumX).

Pay attention to the quadrant of the angle by observing the signs of SumX and SumY.

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