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January 30, 2015

January 30, 2015

Posted by **prethy** on Wednesday, September 8, 2010 at 7:40pm.

x/x-y

would the restrictions be x be 1 and y be zero

- math -
**Henry**, Thursday, September 9, 2010 at 7:37pmRestrictions are values of x and y that causes the denominator to = 0.

x / (x - y),

Set denominator = 0:

x - y = o

solve for x:

x = y,

So when x = y , the denominator = 0.

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