December 21, 2014

Homework Help: Physics (Calc Based)

Posted by Tom on Wednesday, September 8, 2010 at 6:10pm.

I understand how to solve this problem ,however cannot figure out why the .5 degrees is being converted to radians:


How would one determine the percent uncertainty in theta and in sin of theta for the following:

1) theta = 15.0 degrees +/- 0.5 degrees


f(θ) = sin(θ)
f'(θ) = cos(θ)
For θ = 15°
= ±cos(θ) dθ
= ±cos(15°) (0.5°)
= ±0.9659*(0.5*π/180) <---- Why is .5 degrees converted to radians?
= ±0.00843

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