Wednesday

October 1, 2014

October 1, 2014

Posted by **Tom** on Wednesday, September 8, 2010 at 6:10pm.

PROBLEM:

How would one determine the percent uncertainty in theta and in sin of theta for the following:

1) theta = 15.0 degrees +/- 0.5 degrees

SOLUTION:

f(θ) = sin(θ)

f'(θ) = cos(θ)

For θ = 15°

d(cos(θ))

= ±cos(θ) dθ

= ±cos(15°) (0.5°)

= ±0.9659*(0.5*π/180) <---- Why is .5 degrees converted to radians?

= ±0.00843

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