Posted by Ed on Wednesday, September 8, 2010 at 4:46pm.
-10log3= log3^-10= log (1/3^10)
so 10^(log(1/3^10)= 1/3^10
Here is an unconfusing explanation.
log100=2
so 10^2=l0^(log100) by definition.
Have you come across the property of logs that says ..
a^loga k = k
your question fits that pattern after a quick adjustment
10^(-10log3)
= 10^(log 3^(-10))
= 3^-10
= 1/3^10 , so far no calculator
= appr. .000016935
check:
log3 = .47771213
-10log3 = -4.771213
10^-4.771213 = .00016935
Thanks!
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