How many joules (J) are needed to increase the temperature of15.0g of lead from 20 degrees celsius to 40 degrees celsius? (Specific heat of Pb is 0.128J/g degree celsius)

q = mass Pb x specific heat Pb x delta T.

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To find the amount of energy (in joules) needed to increase the temperature of a substance, we can use the formula:

Q = m * c * ΔT

where:
Q represents the amount of energy
m represents the mass of the substance
c represents the specific heat of the substance
ΔT represents the change in temperature

Given:
m (mass of lead) = 15.0g
c (specific heat of lead) = 0.128 J/g °C
ΔT (change in temperature) = 40°C - 20°C = 20°C

Let's substitute these values into the formula:

Q = 15.0g * 0.128 J/g °C * 20°C

Q = 38.4 J

Therefore, 38.4 joules (J) are needed to increase the temperature of 15.0g of lead from 20 degrees Celsius to 40 degrees Celsius.

To find the amount of joules (J) required to increase the temperature of an object, we can use the formula:

Q = m * c * ΔT

where:
Q is the energy in joules,
m is the mass of the object in grams,
c is the specific heat capacity of the substance in joules per gram degrees Celsius,
ΔT is the change in temperature in degrees Celsius.

In this case, we have:
m = 15.0g (mass of lead)
c = 0.128J/g°C (specific heat of lead)
ΔT = 40°C - 20°C = 20°C (change in temperature)

Now, we can substitute these values into the formula:

Q = 15.0g * 0.128J/g°C * 20°C

Calculating:

Q = 38.4J

Therefore, 38.4 joules (J) are needed to increase the temperature of 15.0 grams of lead from 20 degrees Celsius to 40 degrees Celsius.