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July 25, 2014

July 25, 2014

Posted by **ami** on Tuesday, September 7, 2010 at 8:36pm.

- phy -
**drwls**, Tuesday, September 7, 2010 at 9:47pmThe range is 2(V^2/g)*sinA cosA.

The maximum height is (V^2/2g) sin^2A

If range = 3 x (max height),

2sinA cosA = (3/2) sin^2A, and

4/3 = tan A

A = 53.1 degrees

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