Posted by Marcel on Tuesday, September 7, 2010 at 4:42am.
what is the Laplace transform of e^4t(cos 2t) ?

advanced math  jai, Tuesday, September 7, 2010 at 4:57am
since there is e^4t multiplied to cos(2t), there is sshifting:
from e^4t, we know that a = 4,, we also know that L{cos 2t} = s/(s^2 + 4) , therefore:
L{e^4t(cos 2t)} = (sa)/((sa)^2 + 4) = (s4)/((s4)^2 + 4)
so there,, =)

advanced math  Marcel, Tuesday, September 7, 2010 at 5:27am
thanks a bunch.
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