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posted by Marcel Tuesday, September 7, 2010 at 4:42am.

what is the Laplace transform of e^4t(cos 2t) ?

since there is e^4t multiplied to cos(2t), there is s-shifting: from e^4t, we know that a = 4,, we also know that L{cos 2t} = s/(s^2 + 4) , therefore: L{e^4t(cos 2t)} = (s-a)/((s-a)^2 + 4) = (s-4)/((s-4)^2 + 4) so there,, =)

thanks a bunch.

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