college chemistry
posted by summer on .
Calculate the amount of heat required to heat 80 grams of water from 10 to 53°C. The specific heat capacity for water is 4.184 J/g°C.

It takes 4.184 J to heat 1 g of water 1 degree C. How much to heat 80 g water 1 degree C?
Then how much to heat 80 g water (5310) degrees C?
You can also look at the units. You know 4.184 = J/gC Solve this algebraically with your known g (number of grams) and your known C (change in degrees C). solve for J.