Posted by John on Monday, September 6, 2010 at 10:43pm.
sorry to keep posting this, but I have an assignment based on these problems (same equations different numbers) due in a couple hours.
A rocket is launched at an angle of 42◦ above the horizontal with an initial speed of 76 m/s. It moves for 9 s along its initial line of motion with an acceleration of 29 m/s^2. At this time
its engines fail and the rocket proceeds to move as a projectile.
The acceleration of gravity is 9.8 m/s^2.
a.) Find the maximum altitude reached by the rocket.
b.) What is its total time of flight?
c.) What is its horizontal range?
I know how to find these with constant acceleration (I think) but with the increasing acceleration I'm not sure.
Answers are:
a.) 3837.91 m
b.) 59.9965 s
c.) 14152.7 m
Need to know how to solve, thank you.

Physics  drwls, Monday, September 6, 2010 at 10:52pm
Do the prblem in two steps:
(1) constant acceleration phase (engine on)
(2) gravity acceleration only (engine off)
The finsl conditions at the end of phase 1 become the iunitial conditions for phase 2.

Physics  John, Monday, September 6, 2010 at 10:58pm
okay, how do I do step 1? I think if I could figure out how to get to the engine off phase i could solve, as I've done similar problems with just gravity and constant acceleration.
Thanks.
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