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November 28, 2014

November 28, 2014

Posted by **Jack** on Monday, September 6, 2010 at 9:39pm.

This is what i did

i set the density of water .996g/cm^3 = 593.63g-78.23g/V

Solved for Volume of water and got 517.469

then to find density of sulfer i divided 1026.57/517.469

and got D= 1.983 g/cm3

Very confused though due to significant figures and roundings, can some one check my answer and correct me if i am wrong?.

- chemistry -
**DrBob222**, Monday, September 6, 2010 at 10:07pmThis is what i did

i set the density of water .996g/cm^3 = 593.63g-78.23g/V**First, i is I. The original problem lists the density of water as 1.00 g/mL; therefore, you need to correct volume using the proper density value.**

Solved for Volume of water and got 517.469**I think the value is closer to 515 something.**

then to find density of sulfer i divided 1026.57/517.469**Isn't the mass of H2SO4 1026.57-78.23 = ??**

and got D= 1.983 g/cm3**You have 5 s.f. in the water calcn and 3 for the density; therefore, the volume is known to 3 s.f. You can't have more than 3 s.f. in the final answer.**

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