If AD = 20 and AC = 3x + 4, find the value of x. Then find AC and DC

i think you forgot to specify the figure (if it is a parallelogram, triangle, lines, etc)

are AC and DC sides? if so, of what figure?

If ad=20 and ac=3x+4,find the value of x. Then find ac and dc

If ad=20 and ac=3x+4,find the value of x. Then find ac and dc

ac=40 and dc=20

To find the value of x, we can set up an equation using the information given. We know that AD = 20 and AC = 3x + 4. Since AD and AC are segments of the same line, they must be equal. Therefore, we can write the equation:

20 = 3x + 4

To solve for x, we need to isolate it on one side of the equation. Let's start by subtracting 4 from both sides:

20 - 4 = 3x

This simplifies to:

16 = 3x

Now, we divide both sides of the equation by 3 to solve for x:

16 / 3 = x

This gives us:

x ≈ 5.33 (rounded to two decimal places)

Now that we know the value of x is approximately 5.33, we can substitute this value back into the expression AC = 3x + 4 to find the lengths of AC and DC.

AC = 3(5.33) + 4
= 15.99 + 4
≈ 19.99 (rounded to two decimal places)

Therefore, AC is approximately 19.99.

To find DC, we need to subtract the length of AC from AD:

DC = AD - AC
= 20 - 19.99
= 0.01

Therefore, DC is approximately 0.01.