If AD = 20 and AC = 3x + 4, find the value of x. Then find AC and DC
i think you forgot to specify the figure (if it is a parallelogram, triangle, lines, etc)
are AC and DC sides? if so, of what figure?
If ad=20 and ac=3x+4,find the value of x. Then find ac and dc
If ad=20 and ac=3x+4,find the value of x. Then find ac and dc
ac=40 and dc=20
To find the value of x, we can set up an equation using the information given. We know that AD = 20 and AC = 3x + 4. Since AD and AC are segments of the same line, they must be equal. Therefore, we can write the equation:
20 = 3x + 4
To solve for x, we need to isolate it on one side of the equation. Let's start by subtracting 4 from both sides:
20 - 4 = 3x
This simplifies to:
16 = 3x
Now, we divide both sides of the equation by 3 to solve for x:
16 / 3 = x
This gives us:
x ≈ 5.33 (rounded to two decimal places)
Now that we know the value of x is approximately 5.33, we can substitute this value back into the expression AC = 3x + 4 to find the lengths of AC and DC.
AC = 3(5.33) + 4
= 15.99 + 4
≈ 19.99 (rounded to two decimal places)
Therefore, AC is approximately 19.99.
To find DC, we need to subtract the length of AC from AD:
DC = AD - AC
= 20 - 19.99
= 0.01
Therefore, DC is approximately 0.01.