Posted by James on Monday, September 6, 2010 at 7:45pm.
y appears in both equations to the first degree. You can eliminate y by equating the value of y from each equation.
Solve the resulting quadratic equation for x.
Back-substitute the values of x into the equations to get the corresponding values of y.
Substitute x^2 - 3 for y in the second equation.
x + x^2 - 3 = -1
x^2 + x - 2 = 0
(x + 2)(x - 1) = 0
Find the two possible values for x and insert to find y. Insert both sets of values into second equation to check.
Related Questions
Algebra - Solve the equation 5x+7=13-7x graphically. then check your solution ...
pre calculous - solve each equation algebraically and check it by substituing ...
calculus - Please help me solve this equation. log[2](3)+log[2](x)=log[2](5)+log...
System of equation - solve algebraically x^2 + y^2 = 16 x - y = 4
algebra - Solve algebraically and check x^2 + 4y^2 = 4 x = 2y - 2
[math] - How do I solve this equation algebraically? 1/2x + 2/3 = 1/8x - 3/2 ...
Algebra - Solve algebraically and check your potential solutions: sqrt((x+2) -x...
calculus - Please help me? ln(x+1)-ln(x-2)=ln(5) 1. Solve equation by setting up...
pre-cal - solve the equation algebraically. 7e^x=11-e^-x
College Algebra - Solve the exponential equation algebraically: 2^x+1=5^2x
For Further Reading
