Posted by **James** on Monday, September 6, 2010 at 7:45pm.

Solve algebraically and check

y = x^2 - 3

x + y = -1

- equation -
**MathMate**, Monday, September 6, 2010 at 7:51pm
y appears in both equations to the first degree. You can eliminate y by equating the value of y from each equation.

Solve the resulting quadratic equation for x.

Back-substitute the values of x into the equations to get the corresponding values of y.

- equation -
**PsyDAG**, Monday, September 6, 2010 at 7:53pm
Substitute x^2 - 3 for y in the second equation.

x + x^2 - 3 = -1

x^2 + x - 2 = 0

(x + 2)(x - 1) = 0

Find the two possible values for x and insert to find y. Insert both sets of values into second equation to check.

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