Posted by **James** on Monday, September 6, 2010 at 7:45pm.

Solve algebraically and check

y = x^2 - 3

x + y = -1

- equation -
**MathMate**, Monday, September 6, 2010 at 7:51pm
y appears in both equations to the first degree. You can eliminate y by equating the value of y from each equation.

Solve the resulting quadratic equation for x.

Back-substitute the values of x into the equations to get the corresponding values of y.

- equation -
**PsyDAG**, Monday, September 6, 2010 at 7:53pm
Substitute x^2 - 3 for y in the second equation.

x + x^2 - 3 = -1

x^2 + x - 2 = 0

(x + 2)(x - 1) = 0

Find the two possible values for x and insert to find y. Insert both sets of values into second equation to check.

## Answer This Question

## Related Questions

- Algebra - Solve the equation 5x+7=13-7x graphically. then check your solution ...
- pre-calculus 11 - I am asked to solve the absolute value equation of |1/2x +1...
- pre-calculus 11 - I am asked to solve the absolute value equation of |1/2x +1...
- pre calculous - solve each equation algebraically and check it by substituing ...
- calculus - Please help me solve this equation. log[2](3)+log[2](x)=log[2](5)+log...
- math - solve algebraically and check y=8x+3 y=-4x-21 8x+3=-4x-21 +4x +4x 12x+3=-...
- algebra - Solve algebraically and check x^2 + 4y^2 = 4 x = 2y - 2
- calculus - Please help me? ln(x+1)-ln(x-2)=ln(5) 1. Solve equation by setting up...
- Triginometry - Solve the following equations algebraically and check. y=2x^2+2x+...
- Pre-calculus-check answers - Write the slope-intercept form of the equation of ...

More Related Questions