make the subject (p)
p+3=(pq+r)/2
2p + 3 = pq + r
Transpose terms by subtracting pq and 3 from both sides.
2p - pq = r - 3
p(2 - q) = r - 3
p = (r-3)/(2-q)
To solve the equation p + 3 = (pq + r)/2 for the subject p, we need to isolate p on one side of the equation. Here are the steps:
1. Start by multiplying both sides of the equation by 2 to cancel out the denominator:
2(p + 3) = pq + r
2. Distribute the 2 on the left side:
2p + 6 = pq + r
3. Rearrange the equation by moving the term with p to one side:
2p - pq = r - 6
4. Factor out p:
p(2 - q) = r - 6
5. Finally, divide both sides of the equation by (2 - q) to solve for p:
p = (r - 6)/(2 - q)
Therefore, the subject p is equal to (r - 6)/(2 - q).