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December 20, 2014

December 20, 2014

Posted by **jane** on Monday, September 6, 2010 at 11:39am.

a. -sqrt5 = r cos (theta -27degrees)

b. sqrt5 = r cos (theta -27degrees)

c. -sqrt5 = r cos (theta +27degrees)

d. sqrt5 = r cos (theta +27degrees)

is the answer c.

- calculus -
**Reiny**, Monday, September 6, 2010 at 1:54pmmy polar equation would be

2rcosŲ + rsinŲ = 5

r(2cosŲ + sinŲ) = 5

r = 5/(2cosŲ + sinŲ)

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