Friday

April 18, 2014

April 18, 2014

Posted by **jane** on Monday, September 6, 2010 at 11:39am.

a. -sqrt5 = r cos (theta -27degrees)

b. sqrt5 = r cos (theta -27degrees)

c. -sqrt5 = r cos (theta +27degrees)

d. sqrt5 = r cos (theta +27degrees)

is the answer c.

- calculus -
**Reiny**, Monday, September 6, 2010 at 1:54pmmy polar equation would be

2rcosŲ + rsinŲ = 5

r(2cosŲ + sinŲ) = 5

r = 5/(2cosŲ + sinŲ)

**Related Questions**

Pre-Calculus - I need help-I do not understand. The question is this: Write 2x+y...

math - Another: theta is a second quadrant angle in standard position and tan ...

Calculus - I wanted to confirm that I solved these problems correctly (we had to...

math - Another: theta is a second quadrant angle in standard position and tan ...

Pre Cal. - Express 5sqrt(3) - 5i in polar form. A: 10(cos(11pi/6) + i sin(11pi/6...

calculus - Find the length in the first quadrant of the circle described by the...

Calculus still confused - Find the length in the first quadrant of the circle ...

Trig - Sin theta=8/17, theta in Quadrant I, Cos X=-sqrt5/5 in Quadrant II

math - put these polar equations into cartesians form: 1) theta=135 degrees 2)...

Trigonometry (repost Reiny) - at 1:35am I posted ; Write equivalent equations in...