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September 16, 2014

September 16, 2014

Posted by **Leanna** on Monday, September 6, 2010 at 11:37am.

- Calculus -
**MathMate**, Monday, September 6, 2010 at 1:11pmWith x=2 and x=-2 as vertical asymptotes, the denominator of g(x) contains the factors (x-2) and (x+2).

To get 3 and 1 as zeroes, the numerator must contain the factors (x-3) and (x-1).

The horizontal asymptote of y=4 implies that lim x->∞ and x->-∞ g(x) = 4. This is the case when the highest powered term of the numerator divided by the highest power term of the denominator is 4.

Find g(x), and plot the graph to verify your answer.

- Calculus -
**Leanna**, Monday, September 6, 2010 at 6:50pmSo i got g(x)= (4x^2-16x+12)/(x^2-4)

is this correct?

- Calculus -
**MathMate**, Monday, September 6, 2010 at 7:46pmCorrect.

For you reference, see:

http://img94.imageshack.us/img94/1728/1283787460.png

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