Posted by Neha ghatia on Monday, September 6, 2010 at 10:29am.
Nuts to this. If the volume is one liter, you have one liter of Nitrogen, and one liter of oxygen. Gases spread to fill the volume.
If you want the mass percentage, that is easy.
Assume a volume V.
MassV= 1.25V grams.
but massV=molemassAir*molesAir.
now, molesair = PV/RT
molemassAir=massV*RT/PV=1.25RT/P
so calculate that.
Now, molemassAir=32X+28(1-x)
and you can solve for X (percent of O2 by mass).
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