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Posted by **Rebecca S Bhutto** on Monday, September 6, 2010 at 9:18am.

3 1/9 x (-3 3/5) ÷ 2 1/10

INTEGERS

[3x(-3)-4x(-2)+5x2]+[-2x(-3)+8x(-2)-8x2]

- Mathematics -
**drwls**, Monday, September 6, 2010 at 9:44am3 1/9 x (-3 3/5) ÷ 2 1/10

= 28/9 x -18/5 x 10/21

=(-18/9)x(28/21)x(10/5)

= -2 x (4/3) x 2

= -16/3

[3x(-3)-4x(-2)+5x2]+[-2x(-3)+8x(-2)-8x2]

= -9x +8x +5x^2 +6x -16x -8x^2

Now combine terms

-11x -3x^2