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December 18, 2014

December 18, 2014

Posted by **Samantha** on Monday, September 6, 2010 at 3:58am.

y= log 1/7^x

- Math -
**Reiny**, Monday, September 6, 2010 at 9:10amthe way you typed it, it would mean y = 0 , since log1 = 0

if you meant

y = log(1/7^x) then

y = log1 - log7^x

= 0 - xlog7

= -0.8451x which is a straight line

or perhaps did you mean y = (log (1/7))^x ?

- can you see the ambiguity of the question if no brackets are used?

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