Posted by **TAYLOR** on Sunday, September 5, 2010 at 9:47pm.

MACHO ATE 125 HOT DOGS OVER A FIVE DAY PERIOD. EACH DAY HE AT SEVEN MORE HOT DOGS THAN ON THE PREVIOUS DAY. HOW MANY HOT DOGS DID HE EAT ON THE FIRST DAY?

- MATH -
**Reiny**, Sunday, September 5, 2010 at 9:50pm
first day --> x

2nd day --> x+7

etc

x + x+7 + x+14 + x+21 + x+28 = 125

5x = 55

x = 11

- MATH -
**Henry**, Sunday, September 5, 2010 at 10:04pm
x = (x+7) + (x+14) + (x+21) + (x+28) =

125,

5x + 70 = 125,

5x = 125 - 70 = 55,

x = 11.

- MATH -
**Nicole**, Tuesday, September 7, 2010 at 4:27pm
I agree 100% with that answer and I understand all of it besides:

5x + 70 = 125

please help

- MATH -
**Henry**, Tuesday, September 7, 2010 at 7:27pm
X + (X + 7) + (X + 14) + (X + 21) + (X + 28) = 125.

X + X + X + X + X = 5X.

7 + 14 + 21 + 28 = 70.

5X + 70 = 125

5X = 125 - 70 = 55

X = 11.

I'm glad i could help.

- MATH -
**Sriram**, Sunday, May 8, 2011 at 4:48pm
11 hot dogs.

- MATH -
**Elisa**, Tuesday, June 5, 2012 at 9:55pm
Answer 11 hotdogs

- MATH -
**Alyssa**, Wednesday, September 19, 2012 at 7:57pm
the answer is correct it would be 11 hotdogs

- MATH -
**TAYLOR**, Wednesday, October 1, 2014 at 6:49pm
thanks everybody!!!!

- MATH -
**David**, Saturday, November 14, 2015 at 7:36pm
11 hotdogs

- MATH -
**BrAdEn**, Sunday, April 24, 2016 at 7:40pm
The answer would be eleven hot dogs.

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