The number of protons, neutrons and electrons, respectively, in 115Cd2+ are?
To determine the number of protons, neutrons, and electrons in an ion, we first need to identify the atomic number and mass number of the atom.
The atomic number of an element represents the number of protons in its nucleus. The mass number represents the total number of protons and neutrons in the nucleus.
The symbol 115Cd2+ indicates that the element is Cadmium (Cd) and has a charge of 2+.
The atomic number of Cadmium (Cd) is 48. This means it has 48 protons in its nucleus.
To find the number of neutrons, we subtract the atomic number from the mass number. However, since we are given the charge of the ion, the charge also gives us information about the number of electrons.
An ion with a 2+ charge means that it has gained two electrons to become stable. Therefore, the number of electrons in Cd2+ is 48 - 2 = 46.
To find the number of neutrons, we need to know the mass number of Cadmium (Cd). Unfortunately, the mass number is not provided in the question. However, we can assume it is the most common isotope of Cadmium, which is Cd-115.
The mass number is the sum of protons and neutrons, so the number of neutrons can be calculated as follows:
Number of neutrons = Mass number - Number of protons
Number of neutrons = 115 - 48 = 67
So, the number of protons, neutrons, and electrons in 115Cd2+ are 48 protons, 67 neutrons, and 46 electrons, respectively.
To determine the number of protons, neutrons, and electrons in an atom or ion, we need to use the atomic number and the charge of the ion.
The atomic number of an element represents the number of protons in the nucleus of its atoms. For cadmium (Cd), the atomic number is 48. This means that there are 48 protons in the cadmium atom.
Next, we need to consider the charge of the ion. The superscript "2+" indicates that the ion has a positive charge of +2. A positive charge on an ion means that it has lost electrons. In this case, Cd2+ has lost 2 electrons.
Since electrons are negatively charged particles and the overall charge of an atom is neutral, the number of electrons is equal to the number of protons minus the charge of the ion.
So, the number of protons in 115Cd2+ is still 48. To find the number of electrons, subtract the charge of the ion (2) from the atomic number (48).
Number of electrons = Atomic number - Charge of the ion
Number of electrons = 48 - 2
Number of electrons = 46
Finally, to find the number of neutrons, subtract the sum of protons and neutrons from the atomic mass. The atomic mass of cadmium is approximately 115 atomic mass units (amu).
Number of neutrons = Atomic mass - Atomic number
Number of neutrons = 115 - 48
Number of neutrons = 67
Therefore, in 115Cd2+ there are:
- 48 protons
- 67 neutrons
- 46 electrons
Look up the atomic number of Cd (from the periodic table). That is the number of protons.
#protons + #neutrons = mass number(115)
# electrons = # protons in a neutral atom. This atom is not neutral and since the charge is +2 it must have two fewer electrons than protons. You can take it from here.