I have two I need help with!
1. An airplane is flying in a horizontal flight level at constant velocity, heading due east. If the weight of the plane is 2.6 x 10^4 N, what is the net force on the plane?
a)-2.6x10^4 N
b)2.6x10^4 N
c)0.0 N
d) that due to gravity, which is 2.5x10^5 N
e)need to know the thrust, drag, and buoyant force
2a.A 320-kg satellite is in orbit around the earth 16,000km above the earths surface. What is the weight of the satellite when in orbit
a)314 N
b) 320 kg
c) 120 N
d)250 N
e)498 N
2b.Whats the weight of the same satellite when it is on the earths surface, just before being launched?
a)320kg
b)320 N
c) 32.7 N
d)512 N
e) 3100 N
1. Constant velocity means zero net force.
2a. Weight is measured in Newtons, not kg.
W = M g', where g' is less than the value at the earth's surface, g. 16000 km above the Earth's surface is about 22,400 above the center of the Earth, or 3.5 Earth radii. g' = g/(3.5)^2 = 0.80 m/s^2
W = about 250 N
2b. M g = ?
The closest answer is (e), but is off by about 1%
1. To find the net force on the plane, we need to consider the forces acting on the plane. In this case, the plane is flying at a constant velocity, so there are two main forces to consider:
- Thrust force: This is the force produced by the plane's engines to propel it forward. However, since the question does not provide information about the thrust force, we cannot determine its value.
- Drag force: This is the force opposing the motion of the plane, caused by air resistance. Again, we don't have information about the drag force.
Since we don't have information about the thrust and drag forces, we cannot directly determine the net force acting on the plane. Therefore, the correct answer is (e) - we need to know the thrust, drag, and buoyant force.
2a. To find the weight of the satellite when in orbit, we can use the formula for gravitational force:
Weight = mass * gravitational acceleration
Given:
- Mass of the satellite = 320 kg
- Distance from the Earth's surface = 16,000 km
First, we need to convert the distance from kilometers to meters:
Distance from the Earth's surface = 16,000 km * 1000 m/km = 16,000,000 m
Next, we need to find the gravitational acceleration at that distance. The formula for gravitational acceleration is:
Gravitational acceleration = G * (Mass of the Earth) / (Distance from the center of the Earth)^2
Where G is the gravitational constant, approximately 6.67430 x 10^-11 m^3/(kg * s^2) and Mass of the Earth is approximately 5.972 x 10^24 kg.
Plugging in the values, we have:
Gravitational acceleration = (6.67430 x 10^-11) * (5.972 x 10^24) / (16,000,000 + Radius of the Earth)^2
Since the satellite is in orbit, its distance from the center of the Earth is equal to the sum of the Earth's radius (approximately 6,371 km) and the distance from the Earth's surface (16,000 km). So:
Gravitational acceleration = (6.67430 x 10^-11 * 5.972 x 10^24) / (16,000,000 + 6,371)^2
Now we can calculate the weight using the formula:
Weight = mass * gravitational acceleration
Weight = 320 kg * Gravitational acceleration
After substituting the value of gravitational acceleration, we can calculate the weight of the satellite.
2b. When the satellite is on the Earth's surface, just before being launched, it is at a distance of the Earth's surface, which is around 6,371 km. We can use the same formula as in part 2a to find the weight.
Gravitational acceleration = (6.67430 x 10^-11 * 5.972 x 10^24) / (6,371)^2
Weight = mass * gravitational acceleration
Weight = 320 kg * Gravitational acceleration
After substituting the value of gravitational acceleration, we can calculate the weight of the satellite.