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November 28, 2014

November 28, 2014

Posted by **demi** on Sunday, September 5, 2010 at 6:26pm.

- physics -
**Anonymous**, Sunday, September 5, 2010 at 6:56pmhorizontal speed = u = constant = 30 cos 18 so find u

d = u T

so we need T (total time aloft) to know the horizontal distance, d in the air.

so how long in the air?

initial speed up = Vi = 30 sin 18

so find Vi

v = Vi - 9.8 t

at top v = 0 and t = T/2

so

T/2 = Vi/9.8

T = Vi /4.9

put that T back in d = u T to find how far it goes in the air

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